Proving |xy-ab| is Less Than Epsilon: Absolute Value Question | Homework Help"

AI Thread Summary
To prove that |xy - ab| < ε(|a| + |b| + ε) given |x - a| < ε and |y - b| < ε, one approach is to expand |xy - ab| using the triangle inequality. The expression can be rewritten as |xy - x*b + x*b - ab|, which simplifies to |x(y - b) + b(x - a)|. Careful handling of the inequalities during multiplication is crucial, particularly regarding signs. Utilizing the bounds provided by |x - a| and |y - b| can help establish the desired result. The proof requires a systematic approach to ensure all terms are accounted for correctly.
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Homework Statement



Given: |x-a|<ε |y-b|<ε. proove: |xy-ab|<ε(|a|+|b|+ε)


Homework Equations


I need a direction for this proof.


The Attempt at a Solution


I tried by the info: -ε+a<x<ε+a and -ε+b<y<ε+b to ,multiply these inequalities, but it's not true. and i tried with the opposite triangle inequality and it didn't worked.
 
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You can expand |xy-ab| to contain terms like a(y-b) and then use the regular triangle inequality.
The direction multiplication of the inequalities could work, too, but you have to be careful with signs there.
 
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