How can I use physics to determine the inclination of a tilted air hockey table?

  • Thread starter Thread starter Coolbass04
  • Start date Start date
  • Tags Tags
    Air Table
AI Thread Summary
To determine the inclination of a tilted air hockey table, the physics student can start by calculating the time it takes for the puck to travel the length of the table using its velocity of 3.82 m/s. Since the table is frictionless, the puck's drift to the right is solely due to gravity, which introduces a constant acceleration. By applying trigonometry, the student can analyze the components of gravitational acceleration affecting the puck's motion. With the known distance of 2.59 cm and the calculated time, the acceleration can be determined, leading to the calculation of the table's inclination. This approach effectively combines kinematics and trigonometry to solve the problem.
Coolbass04
Messages
2
Reaction score
0
I've been at this dang problem for 4-5 hours now. Still can't understand how to do it. Anyone have any hints or pointers of where to begin, or what to do??

A physics student playing with an air hockey table (a frictionless surface) finds that if she gives the puck a velocity of 3.82 m/s along the length (1.76 m) of the table at one end, by the time it has reached the other end the puck has drifted a distance 2.59 cm to the right but still has a velocity component along the length of 3.82 m/s. She concludes correctly that the table is not level and correctly calculates its inclination from the above information.

That is all the information that is given. Thanks in advance for your help.
 
Physics news on Phys.org
You have a distance and a velocity...this means you can calculate a time. :wink: :wink: :wink:
 
Fun question. Ok well you know since it's a frictionless surface then the slide to the right is entirely due to gravity. However, you have to do a little trig to see exactly how much of the components of gravity are affecting the puck. The first step would be to figure out exactly how much time it took to get to the end of the table. Now that you have a time you can do a few more things. You know that since gravity is accelerating the puck a little to the right that it is under a constant acceleration. Given a position and a time and constant acceleration, you can determine exactly what that acceleration is. That should get the ball rolling in the right direction.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top