Pulley, Motor and Weight Torque Problem

[major.triad]

Pulley and Motor - Torque Problem

Homework Statement

When the motor in the figure below lowers the m = 1140kg mass, it produces a tension of 1.04E+4N in the cable on the right side of the pulley. The pulley has a moment of inertia of 79.7kgm^2 and a radius of 0.741m. The cable rides over the pulley without slipping. Determine the acceleration of the m = 1140kg mass. Use g=9.81m/s^2.
Draw free-body diagrams of the mass and the pulley. Do not assume that the tension in the cable is the same on both sides of the pulley.

Homework Equations

T=rxf

a=α*r where α = angular acceleration
----> a/r=α

The Attempt at a Solution

mg-T_1{} = ma
T_2{} = 10 400 N

r*(T_1{}-T_2{})=I*α
r*(T_1{}-T_2{})=I*(a/r)
T_1{}-T_2{}=I*(a/r^2)
(11 183 - 11 40a) - (10 400) = (79.7/0.741^2)a
783-1140a = 145.15a
783 = 1285.15a
a= 0.609 m/s/s

I'm not sure what I'm doing wrong. The steps all make sense to me, but when I've tried submitting the answer on LON-CAPA it says it's incorrect. Anyone have any ideas?

 

[Spinnor]

Can you add a picture, sketch, or scan of the set-up. One picture is worth a lot of words.