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## Homework Statement

A block with mass 6.00kg resting on a horizontal surface is connected by a horizontal cord passing over a light frictionless pulley to a hanging block with mass 4.00kg. The coefficient of kinetic friction between the block and the horizontal surface is 0.50. After the blocks are released,

a.) Find the acceleration of each block

b.) The tension in the cord.

## Homework Equations

## The Attempt at a Solution

a.)

uk = 0.50

fk = ukN

fk = 0.50(6.00kg)(9.8m/s^2)

Summation of the mass of 6.00kg block

m1a = T - fk

m1a = T - 0.50(6.00kg)(9.8m/s^2)

Summation of the mass of 4kg block

m2a = m2g - T

so i add both the two forces:

m1a = T - 0.50(6.00kg)(9.8m/s^2)

+m2a = m2g - T

________________

(m1+m2)a = m2g - 0.50(6.00kg)(9.8m/s^2)

a = { (4.00kg)(9.8m/s^2) - 0.50(6.00kg)(9.8m/s^2) } / {6.00kg+4.00kg}

a = 0.98m/s^2

dont know how the back of the book got an answer of 0.1m/s^2

b.) m2a = m2g - T

(4.00kg)(.98m/s^2) = (4.00kg)(9.8) - T

T = 35.28N