Two blocks are connected by a thin inextensible string over a frictionless massless pulley
as shown on the picture below
The acceleration of gravity is 9.8 m/s2
Given that the two blocks move at 1.9 m/s
under an acceleration of 4.1 m/s2,
calculate the coeﬃcient µk of kinetic friction between
the left block and the incline.
m2-T = m2*a
*(any and all derived equations as well)
The Attempt at a Solution
Tension minus parallel force of gravity minus force of friction equals zero because its travelling at a constant velocity.
(110kg*(9.8m/s2-4.9m/s2)) - (37kg*9.8m/s2*sin(33)) - (μ*9.8m/s2*37kg*cos(33))
after doing the arithmetic and algebra i got to:
429.5138859N = (μ*9.8m/s2*37kg*cos(33))
Dividing both sides by (9.8m/s2*37kg*cos(33))
i got μ=1.412400969
I got this incorrect twice before and know have noticed my previous errors and fixed them, but was wondering if anyone can verify with me that this is the right/ wrong answer? thanks!
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