1. The problem statement, all variables and given/known data Two blocks are connected by a thin inextensible string over a frictionless massless pulley as shown on the picture below The acceleration of gravity is 9.8 m/s2 Given that the two blocks move at 1.9 m/s under an acceleration of 4.1 m/s2, calculate the coeﬃcient µk of kinetic friction between the left block and the incline. 2. Relevant equations* ƩF=MA Ff=μk*Fn m2-T = m2*a *(any and all derived equations as well) 3. The attempt at a solution Tension minus parallel force of gravity minus force of friction equals zero because its travelling at a constant velocity. (110kg*(9.8m/s2-4.9m/s2)) - (37kg*9.8m/s2*sin(33)) - (μ*9.8m/s2*37kg*cos(33)) after doing the arithmetic and algebra i got to: 429.5138859N = (μ*9.8m/s2*37kg*cos(33)) Dividing both sides by (9.8m/s2*37kg*cos(33)) i got μ=1.412400969 I got this incorrect twice before and know have noticed my previous errors and fixed them, but was wondering if anyone can verify with me that this is the right/ wrong answer? thanks!