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## Homework Statement

Sum of downward forces exerted at A and B is 41lbs by the leg, what is the weight attached?

## Homework Equations

None, really...

## The Attempt at a Solution

Tension (T) throughout the system must be constant and equal to the weight (W).

I first assumed that the leg was entirely pulled up by B since I thought the force passing A

is going down (wrong since this is in equilibrium) and claimed W = 41sin60, but it's not that simple.

Tension pulls both ways, so there is an upward force at A as well as B.

Since

[itex]ƩF_y = 0[/itex]

[itex]Tsin25 + Tsin60 - 41lb = 0[/itex]

[itex]T = W = 41 / (sin25 + sin60) = 31.0lb[/itex]

But using this value of T in checking horizontal forces, they don't balance out.

What am I missing here, or are my calculations correct and there just is a net horizontal force

on the leg that the leg has to resist?

Thanks in advance :).