Sum of downward forces exerted at A and B is 41lbs by the leg, what is the weight attached?
The Attempt at a Solution
Tension (T) throughout the system must be constant and equal to the weight (W).
I first assumed that the leg was entirely pulled up by B since I thought the force passing A
is going down (wrong since this is in equilibrium) and claimed W = 41sin60, but it's not that simple.
Tension pulls both ways, so there is an upward force at A as well as B.
[itex]ƩF_y = 0[/itex]
[itex]Tsin25 + Tsin60 - 41lb = 0[/itex]
[itex]T = W = 41 / (sin25 + sin60) = 31.0lb[/itex]
But using this value of T in checking horizontal forces, they don't balance out.
What am I missing here, or are my calculations correct and there just is a net horizontal force
on the leg that the leg has to resist?
Thanks in advance :).