Q is the quality factor of series resonant circuits

AI Thread Summary
The quality factor (Q) of series resonant circuits is expressed as Q = wL/R, while for parallel resonant circuits, it is Q = R/wL, which can be confusing. The distinction arises from how energy is stored and dissipated in each type of circuit. Loaded resonant circuits include additional components that affect their Q factor, while unloaded circuits do not have these extra elements. To find the Q factor of a loaded resonant circuit, one must consider the effects of the load on the circuit's resistance and reactance. Understanding these concepts is crucial for analyzing circuit performance.
ng
Messages
31
Reaction score
0
Hi all

I read that Q,the quality factor of series resonant circuits is wL/R
------------>1/R sqrt(L/C).This i understand

1.but for parallel resonant it is R/wL...hmm but why is that?this i don quite get.

2.Then what do u mean by loaded resonant circuit and unloaded resonant circuit?

I hope to hear from u guys.
Thanx for ur time and help.
ng
 
Engineering news on Phys.org
Q is defined as the quotient of center frequency over bandwidth. From this definition follow the different formulas for parallel and series circuits.
 
i am sorry to be a dumbo but i wish u spelled it out. :redface:
 
Can someone tell me how to find the Quality factor of a loaded resonant circuit?

PLEASEEEEEEEEEEthanks a lot.
 
Hi all I have some confusion about piezoelectrical sensors combination. If i have three acoustic piezoelectrical sensors (with same receive sensitivity in dB ref V/1uPa) placed at specific distance, these sensors receive acoustic signal from a sound source placed at far field distance (Plane Wave) and from broadside. I receive output of these sensors through individual preamplifiers, add them through hardware like summer circuit adder or in software after digitization and in this way got an...
I have recently moved into a new (rather ancient) house and had a few trips of my Residual Current breaker. I dug out my old Socket tester which tell me the three pins are correct. But then the Red warning light tells me my socket(s) fail the loop test. I never had this before but my last house had an overhead supply with no Earth from the company. The tester said "get this checked" and the man said the (high but not ridiculous) earth resistance was acceptable. I stuck a new copper earth...
I am not an electrical engineering student, but a lowly apprentice electrician. I learn both on the job and also take classes for my apprenticeship. I recently wired my first transformer and I understand that the neutral and ground are bonded together in the transformer or in the service. What I don't understand is, if the neutral is a current carrying conductor, which is then bonded to the ground conductor, why does current only flow back to its source and not on the ground path...
Back
Top