- #1
coffeebeans
- 7
- 0
Hello, i hope i posted this in the correct section..
I have a question:
the potential energy of a body when it is at point P a distance x from a reference point O is given by V = kx^2, where k is a constant. what is the force acting on the body when it is at P?
the correct ans is 2kx in the direction of PO
the ans i got is kx in the direction OP. as work = force x distance, so force required to bring the body to point p is kx^2 / x .
could some please explain why is the correct ans so? thnk u so much!
I have a question:
the potential energy of a body when it is at point P a distance x from a reference point O is given by V = kx^2, where k is a constant. what is the force acting on the body when it is at P?
the correct ans is 2kx in the direction of PO
the ans i got is kx in the direction OP. as work = force x distance, so force required to bring the body to point p is kx^2 / x .
could some please explain why is the correct ans so? thnk u so much!
Last edited: