Quantum particle in a 2 dimensional box

Unskilled
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Homework Statement


I need some help :cry:

http://www.fysik.uu.se/kurser/1tt306/filer/TentKF06+short-answers.pdf

On task 4 a) i don't understand why they have two solutions, one for odd n and the other for even n.
 
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Unskilled said:

Homework Statement


I need some help :cry:

http://www.fysik.uu.se/kurser/1tt306/filer/TentKF06+short-answers.pdf

On task 4 a) i don't understand why they have two solutions, one for odd n and the other for even n.

Hi there, I also study @ Uppsala ;) physics..

It has to do with the parity of the wave functions. Look on the symmetries around x=0. Ground state has zero nodes, 1st excited has one etc. Skiss the potetial and search for symmetry points.
 
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Note there's no qualititative difference between the x and y directions. You could write the wavefunction more symmetrically as:

\psi_{nm} = C \sin \left( n \pi \frac{x-(-A)}{A-(-A)} \right) \sin \left( m\pi \frac{y-0}{B-0}\right)

They just used some trig identities to rewrite this.
 
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To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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