I Quarter-wave plates and Half-wave plates

AI Thread Summary
Quarter-wave plates create a phase shift of λ/4 between their fast and slow axes. When two quarter-wave plates are placed in series with 0 degrees between their fast axes, the resulting effect is different than when they are oriented at 90 degrees. The outcome can be determined by multiplying their Jones matrices, which is essential for understanding the combined optical effect. The order of multiplication matters due to the non-commutative nature of matrix operations. This discussion highlights the importance of matrix multiplication in predicting the behavior of optical systems involving quarter-wave plates.
boby96
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Hi, I am aware that quater-wave plates create a phase shifts of λ / 4 between the fast and slow transmission axis. My question is what happens if we place two quater-wave plates in series so that there is 0 degrees between the fast transmission axis and how would result change if they where placed in series so that there is 90 degrees between fast transmission axis?

Thanks,
 
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Is this a homework question?
 
boby96 said:
Hi, I am aware that quater-wave plates create a phase shifts of λ / 4 between the fast and slow transmission axis. My question is what happens if we place two quater-wave plates in series so that there is 0 degrees between the fast transmission axis and how would result change if they where placed in series so that there is 90 degrees between fast transmission axis?

Thanks,

Just multiply the Jones matrices and you will find the answer.
 
Drakkith said:
Is this a homework question?
No, just that I have covered normal polarisers in series and know how to predict outcome. So was curious if there was any easy and intuitive way of combing quarter wave plates together.

Andy Resnick said:
Just multiply the Jones matrices and you will find the answer.
Thanks, does it matter in what order i multiply them in?
 
boby96 said:
Thanks, does it matter in what order i multiply them in?

Yes, because they are matrices. If the light first goes through retarder '1', then the system matrix is [T]=[2][1]
 
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