How Far is the Third-Order Bright Fringe from the Central Maximum?

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To find the distance between the central maximum and the third-order bright fringe in a double-slit interference pattern, the relevant parameters include the slit separation (0.25 mm), the distance to the screen (1.5 m), and the wavelength of light (680 nm). The formula for the position of bright fringes is y = (m * λ * L) / d, where m is the order of the fringe, λ is the wavelength, L is the distance to the screen, and d is the slit separation. For the third-order fringe (m=3), substituting the values gives the distance from the central maximum. The discussion highlights the need for clarity on using the formula correctly to achieve the desired result. Understanding the relationship between the variables is crucial for solving the problem accurately.
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Homework Statement


Monochromatic light passes through 2 narrow slits 0.25mm apart and forms an interference pattern on screen 1.5m away.If light with a wavelength of 680nm is used,what is the distance between center of central maximum and center of the third-order bright fringes?


Homework Equations



sorry don't have..

The Attempt at a Solution


d=0.25mm ,y=1.5m lambda=680x10^-9, central max=0, third order=3
i tried using sin@=m x lambda /d ,but y is given..i think i should have use it but then i don't know where n when to use..can you please hint me?
 
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sorry,i've done it already,im so sorry..
 
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