Question about 2 ships - vectors?

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Ships A and B depart from the same port, traveling at different angles and speeds. Ship A moves at 35 mph, 20° west of north, while Ship B travels at 40 mph, 10° east of north. To find the distance between the two ships after two hours, vectors can be drawn and the law of cosines applied. The calculation for part A was successfully completed, confirming the distance. For part B, the speed of Ship A as observed from Ship B can be understood by considering relative motion, where if both ships traveled at the same speed in the same direction, Ship A would appear stationary to an observer on Ship B.
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Homework Statement



Ships A and B leave port together. For the next two hours, ship A travels at 35 mph in a direction 20° west of north while the ship B travels 10° east of north at 40 mph.

(a) What is the distance between the two ships two hours after they depart (in miles)?


(b) What is the speed of ship A as seen by ship B (in mph)?


Homework Equations





The Attempt at a Solution



I have no idea how to approach this problem. I believe it is vectors, however as I said I'm not sure. Any help would be greatly appreciated.
 
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Start by drawing 2 vectors from one point, let's say (0,0)
-One vector will go at a 20° angle to the west (of north) and the other will go 10° east (of north)
-Since it's 2 hours you can make the vector length double (70 and 80).
-You will end up have 1 angle, 2 sides
-You can now use the law of cosines to solveI believe this is correct, if not someone will correct me :p

Edit: that's part A.
 
Thank you, that made a lot of sense and I calculated part A correct. How would I calculate part B though? What does speed as seen by the other mean?
 
Pretend you were standing on boat B watching boat A. If both boats were traveling in tje same direction at the same speed, boat A would appear stationary to someone on boat B.
 
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