I What Values Can Ωk Take in the Equation Ωm+Ωr+Ωk=1?

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In the equation Ω_m + Ω_r + Ω_k = 1, Ω_k can take any real number value, but it is constrained by the positivity of Ω_m and Ω_r. If both Ω_m and Ω_r are positive, then Ω_k must be between 0 and 1. A negative Ω_k indicates a positively curved universe, while Ω_k = 0 corresponds to a flat universe, and a positive Ω_k suggests a negatively curved universe. The equation holds true not only for the present but at any time in the universe. Overall, the values of Ω_k are dependent on the curvature of the universe and the values of the other components.
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Let's suppose we have an equation,
$$Ω_m+Ω_r+Ω_k=1$$
In this equation what's the values that ##Ω_k## can take ?
Only 1,0 or -1 ?

Also this equation is true for only "now" or any time in the universe ?
 
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Arman777 said:
Let's suppose we have an equation,
$$Ω_m+Ω_r+Ω_k=1$$
In this equation what's the values that ##Ω_k## can take ?
Only 1,0 or -1 ?

Also this equation is true for only "now" or any time in the universe ?

Assuming the omegas are positive, then ##0 \le \Omega_k \le 1##

If you allow negative values, then ##\Omega_k## can be any real number.

That was the mathematical answer. Rereading your question, I guess you want a cosmological answer. I'll leave that to others.
 
PeroK said:
Assuming the omegas are positive, then ##0 \le \Omega_k \le 1##

If you allow negative values, then ##\Omega_k## can be any real number.
For flat universe we can take ##Ω_k=0##. In example for positive curvature universe then what could be the value of ##Ω_k## ?
A negative value ?

Cause ##Ω_k=-\frac {κ} {a^2H^2}##

Something seems wrong to me. Either this equation only hold for ##Ω_k=0##.

Oh okay I understand
 
For a negative value of ##Ω_k## corresponds to ##Ω>1## which its positively curved universe
For ##Ω_k=0## corresponds to ##Ω=1## which flat universe
For a postive value of ##Ω_k## corresponds to ##Ω<1## which its negatively curved universe

where ##Ω=Ω_m+Ω_r##
 
Arman777 said:
Let's suppose we have an equation,
$$Ω_m+Ω_r+Ω_k=1$$
In this equation what's the values that ##Ω_k## can take ?
Only 1,0 or -1 ?

Also this equation is true for only "now" or any time in the universe ?
##\Omega_k## can be any real number that makes the equation above true. Because ##\Omega_m## and ##\Omega_r## must be positive, ##\Omega_k## cannot be greater than 1. But it can be as negative as you like.

Arman777 said:
For a negative value of ##Ω_k## corresponds to ##Ω>1## which its positively curved universe
For ##Ω_k=0## corresponds to ##Ω=1## which flat universe
For a postive value of ##Ω_k## corresponds to ##Ω<1## which its negatively curved universe

where ##Ω=Ω_m+Ω_r##
This is accurate.
 
kimbyd said:
##\Omega_k## can be any real number that makes the equation above true. Because ##\Omega_m## and ##\Omega_r## must be positive, ##\Omega_k## cannot be greater than 1. But it can be as negative as you like.This is accurate.
Thanks, its more clear now
 
https://en.wikipedia.org/wiki/Recombination_(cosmology) Was a matter density right after the decoupling low enough to consider the vacuum as the actual vacuum, and not the medium through which the light propagates with the speed lower than ##({\epsilon_0\mu_0})^{-1/2}##? I'm asking this in context of the calculation of the observable universe radius, where the time integral of the inverse of the scale factor is multiplied by the constant speed of light ##c##.
Why was the Hubble constant assumed to be decreasing and slowing down (decelerating) the expansion rate of the Universe, while at the same time Dark Energy is presumably accelerating the expansion? And to thicken the plot. recent news from NASA indicates that the Hubble constant is now increasing. Can you clarify this enigma? Also., if the Hubble constant eventually decreases, why is there a lower limit to its value?
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