Question about Applying V^2/r with two different velocities

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The discussion centers on applying the equation V^2/r = -1g to determine the velocity needed for a -1g acceleration in a centripetal force scenario. The user is attempting to design a situation involving a turn and is unsure which velocity to use in the equation. They propose that the final velocity, specifically at the bottom of the arc, should be utilized for the calculation. The equation is then expressed as Final Velocity^2/Radius = -1g. The focus is on clarifying the correct application of the velocity in the context of centripetal acceleration.
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[SOLVED] Question about Applying V^2/r with two different velocities

Homework Statement


I have a problem where I am using the equation V^2/r = -1g to a problem with centripetal force. Basically the question is designing my own situation where i need to have a -1g acceleration on a turn and i decided on the picture below. It is a vertical picture.

Homework Equations


-1g = v^2/r

The Attempt at a Solution



drawing.jpg


I tried figuring out exactly how to get the velocity but I just don't seem to see which velocity to use.
 
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I know that the equation is V^2/r = -1g. I think the velocity I need to use is the final velocity, which is the velocity at the end of the arc, right? So in this case it would be the velocity of the car at the bottom after it has gone around the arc. So if I use the final velocity, the equation will be: Final Velocity^2/Radius = -1g Is this correct?
 
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