Question about conservation of angular momentum for charges

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Angular momentum is conserved for a charge in an electric field because the electrostatic force is radial, resulting in no torque that would alter the angular momentum. The relationship between distance and velocity does not follow the inverse square law for velocity, as force and acceleration do. When a charge moves in an electric field, any increase in distance does not necessarily correlate with an increase in velocity. If a charge starts with no initial velocity, it will follow a radial path, maintaining zero angular momentum unless it has a non-radial component. Overall, the conservation of angular momentum in this context is upheld due to the nature of the forces involved.
maeila
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Why is angular momentum conserved for a charge in an electric field?
 
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Why wouldn't it be?
 
Is the velocity of a charge q moving in an electric field generated by Q inversely proportional to the distance r from q to Q? And if so, why?
 
maeila said:
Is the velocity of a charge q moving in an electric field generated by Q inversely proportional to the distance r from q to Q? And if so, why?

No. Force and hence acceleration are governed by the inverse square law. Not velocity.
 
Then how is the quantity L=qvr sin(a) conserved?
 
What is the trajectory of you particle?
 
maeila said:
Why is angular momentum conserved for a charge in an electric field?
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Angular momentum (rarely, moment of momentum or rotational) is the rotational equivalent of linear momentum. It is an important quantity in physics because it is intrinsically conserving quantity --the total angular momentum of a system remains constant unless acted on by an external force torque.
 
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I don't know, I just can't see how the relation between distance and velocity could justify that.
It made sense in the gravitational field, since when a satellite gets closer it also gets faster. Now, if I have a stationary positive charge and a smaller positive charge in its field, the first charge will accelerate the other to repel it, so with the increasing distance of the second charge there's also an increase in velocity.
 
maeila said:
I don't know, I just can't see how the relation between distance and velocity could justify that.
It made sense in the gravitational field, since when a satellite gets closer it also gets faster. Now, if I have a stationary positive charge and a smaller positive charge in its field, the first charge will accelerate the other to repel it, so with the increasing distance of the second charge there's also an increase in velocity.
https://en.m.wikipedia.org/wiki/Angular_momentumIf You haven't read this article, you could read the pertinent areas of this Wiki Art angular "Conservation of Angular momentum" - - "angular momentum in Orbital mechanics" and '--- "The Law of Areas"
 
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maeila said:
I don't know, I just can't see how the relation between distance and velocity could justify that.
It made sense in the gravitational field, since when a satellite gets closer it also gets faster. Now, if I have a stationary positive charge and a smaller positive charge in its field, the first charge will accelerate the other to repel it, so with the increasing distance of the second charge there's also an increase in velocity.
Well, if the small charge has no initial velocity it will move along a radial direction and the angular momentum will be zero in any position. The angle alpha in your formula is zero. If it has some non-radial component it will have some angular momentum (in respect to the fixed charge). But the electrostatic force is always radial so there will be no torque applied (again, relative to the origin attached to the fixed charge) and no change in the angular momentum.
 

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