- #1

- 191

- 0

## Homework Statement

Note: [tex]\nu[/tex] is del could not find it...

I need to prove the [tex]\nu[/tex]*E=0

and [tex]\nu[/tex] x E=-dB/dt

## Homework Equations

E(s[tex]\phi[/tex]zt)=(Acos(Kz=wt)/s)s^

## The Attempt at a Solution

so for the first one [tex]\nu[/tex]*E=0 I thought it would be

d/ds(E) but what they did was 1/s d/ds(s E) no idea why they did it. Is it because its S^? I thought i remember doing something like this.

for the cross product

d/ds d/d[tex]\phi[/tex] d/dz

E 0 0

...I got the right answer but they got 0+dE/dZ [tex]\phi[/tex]^-1/s dE/d[tex]\phi[/tex] z^

no idea how they got the z^ i thought it was 0, well it does =0 but where did the -1/s come from?

thanks for the help[STRIKE][STRIKE][/STRIKE][/STRIKE]

Last edited: