Question about elastic deformation.

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The discussion revolves around calculating the stress on a copper rod subjected to elastic deformation, with a given modulus of 110 GPa. The rod, with a cross-section of 10 mm x 10 mm, stretches from 1.000 m to 1.001 m, prompting questions about the relationship between stress and strain. The strain can be calculated as the change in length divided by the original length, resulting in a dimensionless ratio. Participants emphasize the importance of converting units appropriately for calculations, particularly in the context of Young's modulus. The thread highlights the fundamental concepts of elastic deformation and the mathematical relationships involved.
da_coolest
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Hi.. I need a good explanation for the following question. an explanation with a small mathematical calculation to prove the answer would be highly helpful.

A copper rod of cross-section 10 mm  10 mm is stretched along its axis, changing length from 1.000 m to 1.001 m. The deformation is elastic, or fully recoverable. Given that the modulus of copper is 110 GPa, the stress on the rod is approximately (choose the closest answer):

A 110 kPa
B 110 MPa
C 110 GPa
D 1/110 MPa
E 1/110 GPa



thanks in advance!
 
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What is the relationship between stress and strain for elastic deformation?

What is the strain for a bar stretched 1.000 m to 1.001 m?
 
Astronuc said:
What is the relationship between stress and strain for elastic deformation?

What is the strain for a bar stretched 1.000 m to 1.001 m?

young's modulus

thanks, now i got an idea about how to do the calculation. to which units i should convert these into when calculating?
 
da_coolest said:
young's modulus

thanks, now i got an idea about how to do the calculation. to which units i should convert these into when calculating?

Strain is a ratio, and is dimensionless, or written as m/m or cm/cm or in/in.
 

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