According to Gauss's Law, the electric flux through a closed surface is equal to the charge enclosed by the surface divided by epsilon_0. This obviously excludes charges outside the surface. But what about *on* the surface? That is, it lies neither inside nor outside. Does this charge count as being "enclosed" in the sense of Gauss's Law? In other words, does the electric field of a charge "on" a closed surface create a nonzero flux through the surface? Any help would be greatly appreciated. Thank You in Advance.