Question about making vectors equilibrium

AI Thread Summary
To achieve equilibrium with two forces of 4.6 N at a 40° angle, a third force must counterbalance their resultant. The discussion emphasizes that equilibrium means the net force and acceleration are zero, requiring precise calculations for the third force's magnitude and direction. The initial attempt to calculate the third force involved incorrect angle adjustments, leading to confusion about the correct magnitude. The correct approach involves using vector addition to derive the third force from the first two forces. Ultimately, understanding the relationship between the forces is crucial for determining the magnitude of the third force needed for equilibrium.
preluderacer
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Homework Statement



The figure shows two forces of equal magnitude acting on an object. If the common magnitude of the forces is 4.6 N and the angle between them is 40°, what third force will cause the object to be in equilibrium?


The Attempt at a Solution




What I did was split them down the middle, then used 4.6cos(40) degrees and then got 4.3N I just pointed it in the opposite direction to make it equilibrium. Does this sound like the correct method to use?
 
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What is the definition of equilibrium? What does equilibrium mean for the sum of forces on the object?
 
It means they are balanced right? I thought by pointing the vector in the opposite direction balances it.
 
"Pointing the vector in the opposite direction" is the right idea, but we need to be more mathematically precise than that to solve the problem.

Equilibrium means that the object doesn't move. What does that say about the acceleration of the object? What does that imply about the sum of forces on the object?
 
The original opened up leftward. I messed up when stating it. When I split them i also split the degrees so I used 4.6Ncos(20) degrees. I wound up with 4.3 N pointed toward the left My logic is that it has to be pointed to the right to balance out the forces to make them zero. Is 4.3N the right magnitude of the 2 velocities?
 
From what you describe, you have the direction of the 3rd vector correct. If you'd answer my questions from post #4, you'd have a strong hint about how to compute the magnitude of the force.
 
It means the acceleration is zero. I am so confused are u implying that my magnitude is wrong?
 
preluderacer said:
It means the acceleration is zero. I am so confused are u implying that my magnitude is wrong?

I'm just trying to explain to you how to verify whether your magnitude is correct. If the original 2 vectors were more complicated, your method would not have worked.

If the acceleration is zero, what does that imply about the sum of all of the forces? Rearranging the sum will give you a relationship between the 3rd force and the other two. This will let you compute the magnitude of the 3rd force.
 
The sum of forces are zero
 
  • #10
Can you write an expression for the 3rd force in terms of the first two? How about computing the magnitude of the 3rd force from that?
 
  • #11
You're losing me =( sorry. Iam so confused now.
 
  • #12
\vec{F}_1+\vec{F}_2+\vec{F}_3=0,

can you solve this for \vec{F}_3? Then compute |\vec{F}_3|.
 
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