Question about parallel plate stuff

AI Thread Summary
The discussion revolves around calculating electric field, force on a K+ ion, potential difference, and kinetic energy related to a parallel plate capacitor model of a cell membrane. The electric field between the membranes is calculated to be approximately 1*10^6 N/C, while the force on a K+ ion is determined to be 2*10^-13 N. The potential difference between the walls is found to be 1*10^-2 V. A user is struggling with calculating the kinetic energy of a 7 fC charge, arriving at 7*10^-17, while the expected answer is 8*10^-17. The conversation emphasizes the importance of maintaining significant figures throughout calculations for accuracy.
johnknee
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Homework Statement


A cell membrane consists of an inner and outer wall separated by a distance of approximately 10 nm. Assume that the walls act like a parallel plate capacitor, each with a charge density of 10^−5C/m^2, and the outer wall is positively charged. Although unrealistic, assume that the space between cell walls is filled with air.

Part A
What is the magnitude of the electric field between the membranes? Answer: 1*10^6 N/C

Part B
What is the magnitude of the force on a K+ ion between the cell walls? Answer: 2*10^-13 N

Part C
What is the potential difference between the cell walls? Answer: 1*10^-2 V

Question : If released from the inner wall, what would be the kinetic energy of a 7 fC charge at the outer wall? 1fC = 10^−15C.

Homework Equations


KE = q*Delta(v)

The Attempt at a Solution


I have solved each of the other parts of this question. I found that Delta V was 1×10^−2V. The question states that 1fC is 10^-15 C. I plugged in for KE = (7*10^-15)(0.01V), and keep getting 7*10^-17. However the answer is 8*10^-17. Can anyone catch my mistake, or am i using the wrong formula?
 
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Hi johnknee. :welcome:

There is a figure to accompany this problem, I believe?
 
johnknee said:

Homework Statement

How did you compute part A? Your answer is low by about 11.3%.
 
For part A, I used the equation E = charge density/Permittivity of free space = 10^-5/(8.85*10^-12) = 1*10^6 N/C
 
johnknee said:
10^-5/(8.85*10^-12) = 1*10^6 N/C
= 1.13×106 N/C
 
johnknee said:
For part A, I used the equation E = charge density/Permittivity of free space = 10^-5/(8.85*10^-12) = 1*10^6 N/C
Your calculator needs to show more decimal points!
 
Yeah I have many decimal points haha, it's just that the answer given by masteringphysics is in 1 sig fig.
 
johnknee said:
Yeah I have many decimal points haha, it's just that the answer given by masteringphysics is in 1 sig fig.
Well, yer' not likely to master it with that! LOL
 
johnknee said:
Yeah I have many decimal points haha, it's just that the answer given by masteringphysics is in 1 sig fig.
It's ok to round the answer to 1 sig fig to match the precision of the inputs, but you should keep more digits throughout the calculation in between.
 
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