craigi said:
So you have two answers to your question:
No based upon semantic objections to your question.
Yes from a well respected group of physicists, who made the observation themselves.
You choose.
First we need to be clear about what we are "choosing". The issue here is that the term "virtual particle" is being used in this thread to mean two different things:
Bhobba is using "virtual particle" to mean, roughly speaking, "an internal line in a Feynman diagram". It's impossible to observe one of those, so the answer with this meaning is obviously "no". While it's true that many sources don't use the term "virtual particle" with this meaning, it does happen to be the original meaning of the term, since describing internal lines in Feynman diagrams was what the term was
invented for. The fact that so many sources have not respected this original usage illustrates the problems you get into when you try to use ordinary language instead of mathematics to describe scientific theories.
The paper you linked to is using "virtual particle" to mean, roughly speaking, "a mode of the quantum field". It's certainly possible to observe one of those: just induce a state transition in the mode and then have it interact with a detector. In the paper, the "mirror" (actually a SQUID device being tuned appropriately) adds energy to EM field modes, and that energy is then detected as photons--basically the field modes just transfer the energy from the SQUID to the detector, and the intermediate carrier of the energy is called a "photon"--a "virtual" photon when the corresponding field mode is in its ground state, which then turns into a "real" photon when the mode is excited by the SQUID. So on this interpretation, the answer is obviously "yes"; there are lots of ways of exciting quantum field modes and then observing the results of the excitation.
In the case of the Unruh effect, the key is that a given state of the quantum field can be a "vacuum" state to an inertial observer--i.e., an inertial detector detects no particles--zero probability of a state transition--but not to an accelerated observer, i.e., an accelerated detector has a nonzero probability of undergoing a state transition that we interpret as "detecting a particle". Once again, if we interpret "virtual particle" to mean "a mode of the quantum field", then this is just another example of a "yes" answer to the question: the accelerated detector is just another interaction with a quantum field mode. It's worth noting that, from the viewpoint of an inertial observer, this interaction looks like the
emission of a particle, rather than the
detection (and consequent absorption) of one; in the inertial viewpoint, what happens is that some of the energy that is being pumped into the accelerating detector in order to accelerate it gets transferred to a quantum field mode, which transitions from the "ground" state (at least, the ground state from the viewpoint of the inertial observer) to an "excited" state.
So what we actually need to choose is a single consistent interpretation of the term "virtual particle". Even better, we could taboo that term altogether for this discussion, and ask the OP to restate his question without using it. Then we would know which answer to give.