Question on calculating load on tidal movement

AI Thread Summary
Calculating wind load involves using the formula F = (1/2)*rho*C*V^2, where rho represents the fluid density, C is the drag coefficient, and V is the wind speed. The discussion raises the question of whether this formula can be adapted for tidal movement by considering the density of saltwater, which is significantly greater than air. It is noted that the coefficients for lift and drag differ, complicating the calculations. The user expresses frustration over the lack of straightforward answers from consulting engineers and seeks guidance on finding reliable resources. Ultimately, the forum does not allow for recommendations of specific services or individuals for further assistance.
jamesd442001
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Calculating wind load is windspeed x itself x.00431 x sq. ft. of area. A 100 sq.ft vertical wing in a five mph wind is 10.77 lbs. The mass of salt water is around 854 times that of air. Can you use the wind formula and multiply by 854? Also, does this change with the weight of water at different atmospheres?
 
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The basic equation you are describing is
F = (1/2)*rho*C*V^2
which is used for all sorts of turbulent flow force calculations. The trick is to have the correct C for the force component you want to calculate. It is common to distinguish between a lift and a drag force component, where each has its own coefficient (C-value).

I suggest you do some reading on fluid mechanics before you try to make these calcs to be sure you know what you are doing.
 
I'm more of a mechanical individual looking for the short answer at this point. There is quite a bit more to this than I'm showing. I,ve engaged several consultant engineers at this point to no avail. So if there is not a short answer can you direct me to someone or a service capable of the short and long answer?
 
Unfortunately, no. That is not permitted on this forum.
 
I think it's easist first to watch a short vidio clip I find these videos very relaxing to watch .. I got to thinking is this being done in the most efficient way? The sand has to be suspended in the water to move it to the outlet ... The faster the water , the more turbulance and the sand stays suspended, so it seems to me the rule of thumb is the hose be aimed towards the outlet at all times .. Many times the workers hit the sand directly which will greatly reduce the water...
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