Question on finite and geometric series

AI Thread Summary
The discussion focuses on solving two mathematical problems involving finite and geometric series. The first problem requires finding the exact sum of a series represented as S_n = (2 + 2 + 2(2 + ... + 64), where the "..." indicates a continuation of the pattern until reaching 64. Participants clarify that the series is geometric, with the common ratio being √2, and help derive the closed form for the sum. The second problem involves demonstrating that the sum of the first 10 terms of one geometric series is twice that of another, leading to discussions about the relevant formulas and calculations. Overall, the conversation emphasizes understanding series patterns and applying geometric series formulas effectively.
Luceian K
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1. 1. Find the exact(no approximations)sum for the finite series

S sub n= (2 + 2 + 2(2+...+64

i used the parentheses to represent a radical sign

2. Show that the sum of the first 10 terms of the geometric series

1 + 1/3 + 1/9 + 1/27+...

is twice the sum of the first 10 terms of the series

1 - 1/3 + 1/9 - 1/27+...




2. no relevant equations to solve this.


3. I attempted to solve this by dividing n/2(a sub 1 +a sub n). n would equal 64 and a sub one would equal radical 2 so 64/2 (radical 2 +64).

This is as far as I have been able to get and am not sure if it is the correct way to solve these two problems. I would appreciate if someone could show me step by step how to go about these since my pre-calc book does horribly at it.
 
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Luceian K said:
1. 1. Find the exact(no approximations)sum for the finite series

S sub n= (2 + 2 + 2(2+...+64

i used the parentheses to represent a radical sign
So that is n= \sqrt{2+ 2+ 2\sqrt{2+ ...+ 64}}?
What does the "..." represent?

2. Show that the sum of the first 10 terms of the geometric series

1 + 1/3 + 1/9 + 1/27+...

is twice the sum of the first 10 terms of the series

1 - 1/3 + 1/9 - 1/27+...




2. no relevant equations to solve this.
I would think that
\sum_{i=0}^n r^i= \frac{1- r^{n+1}}{1- r}
would be a very relevant equation!


3. I attempted to solve this by dividing n/2(a sub 1 +a sub n). n would equal 64 and a sub one would equal radical 2 so 64/2 (radical 2 +64).

This is as far as I have been able to get and am not sure if it is the correct way to solve these two problems. I would appreciate if someone could show me step by step how to go about these since my pre-calc book does horribly at it.
 
the "+...+64" is not under the radical sign. Just 2)2. and the "..." is in the question, I don't know what it stands for. I am at a complete loss with these two questions. and my math book doesn't go into enough detail with these types of equations.
 
Luceian K said:
1. 1. Find the exact(no approximations)sum for the finite series

S sub n= (2 + 2 + 2(2+...+64
Is this S_n= \sqrt{2} + 2 + 2\sqrt{2}+...+64 = \sum_{1\le k \le 12} 2^{k/2} ?

if so, then it's a geometric series. Do you know the closed form of the sum of a geometric series?
If not, here's how to get it

S = a + ax + ax^2 + ... + ax^n = \sum_{0 \le k \le n} ax^k

Sx = ax + ax^2 + ax^3 + ... + ax^{n+1}

S - Sx = S(1-x) = a- ax^{n+1}

so S = a\frac{1-x^{n+1}}{1-x}
 
so the equation would not be n/2(a sub 1 + a sub n)
 
HallsofIvy said:
So that is n= \sqrt{2+ 2+ 2\sqrt{2+ ...+ 64}}?
What does the "..." represent?


I would think that
\sum_{i=0}^n r^i= \frac{1- r^{n+1}}{1- r}
would be a very relevant equation!

for the second problem could you tell me how to find r i am unsure of how to solve for that variable
 
Sorry but I don't understand what you're asking. You don't have to solve for anything, just set r=\sqrt{2} (or x=\sqrt{2} in my post) because a=1 in your equation.
 
qntty said:
Sorry but I don't understand what you're asking. You don't have to solve for anything, just set r=\sqrt{2} (or x=\sqrt{2} in my post) because a=1 in your equation.

then i am not sure what n would be in the equation you have there.
 
Luceian K said:
and the "..." is in the question, I don't know what it stands for. I am at a complete loss with these two questions. and my math book doesn't go into enough detail with these types of equations.

Well I guess that's the problem. Ellipses mean that you follow the pattern that has been set until you get to 64 (in this case).

For example 2+4+8+16+...+512 is shorthand for 2+4+8+16+32+64+128+256+512.

In your problem, the patter is that the next term in the series is generated by multiplying the previous term by \sqrt{2}
 
  • #10
Luceian K said:
then i am not sure what n would be in the equation you have there.

the final term in a geometric series can be written in the form ax^n for some number n. The equation which you have is

\sqrt{2} + (\sqrt{2})^2+ (\sqrt{2})^3+ ... + (\sqrt{2})^{12}

So n=12
 
  • #11
i got 216.09545 is this correct
 
  • #12
Luceian K said:
i got 216.09545 is this correct

Yes, that's correct. Now try the other problem.
 
  • #13
thank you for your help
 
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