Calculating Distance Traveled with Kinetic Friction (Coefficient 0.2)

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To calculate the distance a pop can slides before stopping due to kinetic friction, the initial velocity is 2 m/s, and the coefficient of kinetic friction is 0.2. The force of friction can be expressed as a function of the unknown mass, which ultimately cancels out in the equations used. The net force acting on the can is solely due to friction since there are no other horizontal forces involved. The calculated distance traveled before coming to a stop is 1 meter, demonstrating that the mass does not affect the result. Understanding the relationship between friction and motion is crucial for solving such problems.
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Homework Statement


A pop can is sliding across a table and then eventually comes to a stop. If it's initial velocity is 2m/s and the coefficient of kinetic friction between the two surfaces is 0.20, how far will it travel across the table.
Vi=2m/s
Vf=0m/s
CoeffKineticFriction = 0.2

Homework Equations


Fnet = ma
(vf-vi)/t = a

The Attempt at a Solution


I know that there is a force of friction and the coefficient is 0.2, but i don't know the mass of the object to find the normal force.
 
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As you noted: Fnet = ma and Fnet = us X Fn.

Can you expand Fn? Will the unknown mass cancel?
 
edgepflow said:
As you noted: Fnet = ma and Fnet = us X Fn.

Can you expand Fn? Will the unknown mass cancel?
Nope, that's all the question says. It says "Pop Can", and there is a correct answer for it which is 1 metre.
 
What edgepflow was hinting at was that if you express the normal force in terms of the unknown mass m, then the mass will cancel from both sides of the equation. So the result is independent of mass.
 
The only force is the friction force because it is sliding there is no other force.
 
iRamie said:
The only force is the friction force because it is sliding there is no other force.

That's true...in the horizontal direction at least. I'm not sure what you're getting at with your statement.

Did you try taking our advice?
 
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