Question on Le Chatelier's theory?

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SUMMARY

The discussion centers on Le Chatelier's principle in the context of a reversible exothermic reaction, A + B --> C + D, where a heater increases the system's temperature by 10 degrees Celsius. The consensus is that while the reaction will shift to the left to counteract the temperature increase, the continuous heat supply from the heater will prevent the temperature from returning to the original state, resulting in a final temperature of X + 10 degrees Celsius. This illustrates the principle that a system at equilibrium will adjust to minimize the effect of external changes, but in this case, the external heat input overrides the reaction's attempt to restore equilibrium.

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Homework Statement



I have a system which is at X degree celsius. I decide to put in a heater which will heat the system up by 10 degree celsius and will keep supplying this much heat. The reaction taking place is:

A + B --> C + D (it's a reversible reaction)
(enthalpy change is negative-> Exothermic)

I know the reaction will move to the left, but will the temperature of the system be X? Or X + 10?

I mean the reaction is moving backwards in order to eliminate these disturbance in temperature, will it succeed in lowering the temperature to X? Or will it just keep trying by continuously favouring the backward reaction?



The Attempt at a Solution



I formulated this question myself because of my misunderstanding.
 
Last edited:
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I think the answer is X + 10. The reaction will move to the left, but the temperature of the system will be X + 10 because the heater is continuously supplying heat.
 

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