Question on work energy and power kinetic energy of an ....

AI Thread Summary
The discussion revolves around a homework problem where the kinetic energy of a vehicle is said to double when its speed increases by 2 m/s. The user attempts to derive the original speed using the kinetic energy formula, leading to a quadratic equation. After some initial confusion and errors in applying the quadratic formula, the correct solution is found to be u = 2(√2 + 1). Participants emphasize the importance of careful calculations and checking work to arrive at the correct answer. The thread highlights the collaborative effort in problem-solving within the context of physics.
Mr.maniac
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Homework Statement


If the speed of a vehicle increases by 2m/s then it's kinetic energy is doubled. Find out the original speed of the vehicle

Homework Equations


1/2(mv^2)

The Attempt at a Solution


First find out both KE(kinetic energy) taking u(initial vel.)
And v(final vel.) And mass as m
K(initial KE)= 1/2(mu^2)
K`(final KE)=1/2(mv^2)
=1/2[m(u+2)^2]. {Given "speed of vehicle increases by 2m/s}

Also
2K=K`
Then equating
2[1/2(mu^2)]=1/2[m(u+2)^2].
=>mu^2=1/2(mu^2+4m+4mu)
=>u^2=1/2(u^2+4+4u) {dividing m on both sides}
=>2u^2=u^2+4+4u
=>0= -u^2+4+4u.
{Further using quadratic formula}
We get
u=(√2+1)÷2
Sadly that ain't there in the options so. :~( {booo}
 
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Mr.maniac said:

Homework Statement


If the speed of a vehicle increases by 2m/s then it's kinetic energy is doubled. Find out the original speed of the vehicle

Homework Equations


1/2(mv^2)

The Attempt at a Solution


First find out both KE(kinetic energy) taking u(initial vel.)
And v(final vel.) And mass as m
K(initial KE)= 1/2(mu^2)
K`(final KE)=1/2(mv^2)
=1/2[m(u+2)^2]. {Given "speed of vehicle increases by 2m/s}

Also
2K=K`
Then equating
2[1/2(mu^2)]=1/2[m(u+2)^2].
=>mu^2=1/2(mu^2+4m+4mu)
=>u^2=1/2(u^2+4+4u) {dividing m on both sides}
=>2u^2=u^2+4+4u
=>0= -u^2+4+4u.
{Further using quadratic formula}
We get
u=(√2+1)÷2
Sadly that ain't there in the options so. :~( {booo}
Check your work in using the quadratic formula.
 
Will do
 
OK redid it made a slight mistake but it's still no good

u=(-1+/-√2)÷2
 
The +/- means plus or minus or this ± sorry didn't notice the sign before
 
Mr.maniac said:
OK redid it made a slight mistake but it's still no good

u=(-1+/-√2)÷2
That's also wrong.

Show your steps.

(The initial try looked better.)
 
Mr.maniac said:
=>0= -u^2+4+4u.
{Further using quadratic formula}
We get
u=(√2+1)÷2
Your quadratic looks good, but redo your application of the quadratic formula.

(Edit: SammyS beat me to it!)
 
OK got the mistake the ans now is 2(√2+1)
Which is correct I was taking the denominator wrong thank you very much for pointing that out
 
Thank you all for helping
 
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