Questions on the basic principles of physics.

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Velocity can be expressed in various units, including m/s, mph, and km/h, representing the change in distance over time. The value of g, the acceleration due to Earth's gravity, is approximately 9.81 m/s² or 980 cm/s². For an object starting from rest and traveling a distance d in time t, the equation to find acceleration is a = 2d/t². The gravitational constant, denoted as G, is different from g and is valued at approximately 6.674 x 10^-11 m³/(kg·s²). Understanding these principles is essential for grasping basic physics concepts.
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Really isn't involving problems, just principles of physics.


What are the units of velocity?

Im aware of m/s, but I hear there are more.

What is the value of "G"?

If an object starts from rest and travels a distance d in t sec, what equation may be used to find its acceleration?


Really all I need help on.
 
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MoreZitiPlease said:
Really isn't involving problems, just principles of physics.


What are the units of velocity?

Im aware of m/s, but I hear there are more.

What is the value of "G"?

If an object starts from rest and travels a distance d in t sec, what equation may be used to find its acceleration?


Really all I need help on.

Average velocity is the change in unit distance per the change in unit time. (m/s, mph, feet/sec. km/h, etc).

Instantaneous velocity is the rate of change in position per the rate of change per unit time. Same units.

The value of g is 9.8 \frac{m}{s^2} or 32.2 \frac{ft}{s^2}

Equation of motion:

x=x_0+vt+\frac{1}{2}at^2 Solve for a
 
Hey, I made a new thread.

I don't think you properly understood the question.

See my new thrad.
 
And I know the value of G is 9.8 we

but It would be 980cm/m2

right
 
MoreZitiPlease said:
And I know the value of G is 9.8 we

but It would be 980cm/m2

right

Centimeters per meter-squared? No. In centimeters, it would be \frac{cm}{s^2}
 
Velocity could be measured in any distance units divided by any time units.

The acceleration caused by Earth's gravitational field, at the surface of the Earth, is normally denoted by g (not G) and is 9.81 meters per second per second.

If your object is accelerating at a constant rate then the equation to use is
d = 0.5 at^2
a = 2d / t^2
 
Yra I know it is 9.80 meters, but they want to convert it into centimeters. So it would b 980?
 
MoreZitiPlease said:
Yra I know it is 9.80 meters, but they want to convert it into centimeters. So it would b 980?


Yes. Use google as a calculator. Put in the following "9.8 meters to cm", click "search" and you get out the following: 9.8 meters = 980 centimeters

It even does automatic unit conversions. Put in "9.8 m + 32.2 ft", click "search and get back:

(9.8 meters) + (32.2 feet) = 19.61456 meters

How about this:

"50 mph + 10 m/s" "search"

(50 mph) + (10 (m / s)) = 32.35200 m / s

Pretty damn cool, huh?
 
Velocity is loosely a change in a position (distance) divided by the time interval that it took to change position.

So it will always be a distance over a time. Big G is called the gravitational constant( 6.673*10^-11 \frac{m^3 s}{kg}). Little g is acceleration due to gravity (GM/R^2). On the surface of the Earth we can roughly measure it to (9.80m/s^2)
 
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