Quick complex numbers question in QM (probability amplitues)

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This discussion clarifies the application of the functions Re and Im in the context of probability amplitudes in quantum mechanics, specifically in Stern-Gerlach measurements. The user successfully derives the probabilities for deflection in the x and y directions using complex numbers, leading to the expressions Prob(± in x) = 1/2 ± Re(α*β) and Prob(± in y) = 1/2 ± Im(α*β). The user also confirms the relationships between the real and imaginary parts of complex numbers, ultimately resolving confusion regarding the imaginary component through multiplication by i.

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[RESOLVED] Quick complex numbers question in QM (probability amplitues)

Im a little confused here. I am reading in my textbook about probability amplitudes in Stern Gerlach measurements, and it says this:

We find the resulting probabilities for deflection of \left(\stackrel{\alpha}{\beta}\right) in the x and y directions as:

Prob(\pm in x) = \left|\frac{\alpha\pm\beta}{\sqrt{2}}\right|^2 = \frac{1}{2}(|\alpha|^2 + |\beta|^2 \pm \alpha*\beta \pm \beta*\alpha) = \frac{1}{2} \pm Re(\alpha*\beta)

Prob(\pm in y) = \left|\frac{\alpha\mp i\beta}{\sqrt{2}}\right|^2 = \frac{1}{2}(|\alpha|^2 + |\beta|^2 \mp i\alpha*\beta \mp i\beta*\alpha) = \frac{1}{2} \pm Im(\alpha*\beta)


Now I understand where the amplitudes come from and everything, the thing I don't understand is the functions Re and Im, and how they simplified the amplitudes to

\frac{1}{2} \pm Re(\alpha*\beta)

and

\frac{1}{2} \pm Im(\alpha*\beta)

So can someone please explain these functions Re and I am and how they work here?
 
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Any complex number z can be written in the form z=x+iy, where x and y are real numbers called the real part and the imaginary part of z respectively. x and y are uniquely determined by this decomposition, i.e. if x'+iy'=x+iy, then x=x' and y=y'. So there exists a function that takes a complex number to its real part, and a function that takes a complex number to its imaginary part. These functions are called Re and I am respectively.

Note that

z=Re z + i I am z
z*=Re z-i I am z

and that this implies

Re z=(z+z*)/2
Im z=(z-z*)/(2i)

Now what do you get when you compute the real and imaginary parts of \alpha^*\beta?
 
OH! so:

1/2 + Re(a*b) = 1/2 + (a*b + b*a)/2 = 1/2 (1 + a*b + b*a)

but 1 = |a|2 + |b|2

so we get:

1/2 + Re(a*b) = 1/2 (|a|2 + |b|2 + a*b + b*a)

woohoo, thanks a lot!

EDIT: Ok I am not seeing the I am part though:

1/2 + Im(a*b) = 1/2 + (a*b - b*a)/2i = (i + a*b - b*a)/2i ??

I can't seem to get the result in the book of 1/2 (|a|2 + |b|2 - ia*b + ib*a)

EDIT: Oh you just multiply top and bottom by i and it works out! got it, thanks agian!
 
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