Quick convolution integral checking

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Homework Statement



Consider a linear system with the impulse response:

g(t) = 3x^2 - 4x + 7 for t>0 and 0 otherwise.

Find the output for the input f(t) = t for t \geq 0 and f(t) = 0 for t<0.

Homework Equations



\[ \int_{-\infty}^t f(t - \tau)g(\tau)\,d\tau\]


The Attempt at a Solution



\[ \int_0^t f(t - \tau)g(\tau)\,d\tau\]

\[ \int_0^t (t - \tau)(3\tau^2 - 4\tau + 7\,d\tau\)]

and the answer I keep getting is

\frac{t^4}{4} - \frac{2t^3}{3} + \frac{7t^2}{2}

whereas the official given answer has the sign in the middle term as a plus: +\frac{2t^3}{3}

I've even tried wolfram and I think I'm correct:

http://img58.imageshack.us/img58/8637/mspzk2.gif (obviously with different variables - x instead of tau, but still evaluted between t and 0).

If anyone could clear up the correct answer that would be much appreciated.
 
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...anyone?
 
Even I got the same answer as you. So I guess not much of a help.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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