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Quick integral question

  1. Feb 17, 2008 #1
    How do I find the integral of:

    1/[9.8 - (1/245)v^2]
  2. jcsd
  3. Feb 17, 2008 #2


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    Write the denominator as the difference of two squares and factor it. As in a^2-b^2=(a-b)*(a+b). Then use partial fractions.
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