Quick Kinetic Energy question - only confirmation of answer needed.

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Homework Help Overview

The discussion revolves around calculating the change in kinetic energy for a car as it accelerates from 30 km/h to 60 km/h, focusing on the application of the kinetic energy formula.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the change in kinetic energy using the formula KE=1/2mv^2 and questions the correctness of their calculations. They also inquire about the source of the energy gain associated with the change in velocity.

Discussion Status

Some participants confirm the original poster's calculations and provide insights into the source of the energy gain, discussing factors such as the engine and the driving force involved in the car's motion. Multiple interpretations of the energy source are being explored.

Contextual Notes

The discussion includes a request for confirmation of calculations and an explanation of the energy source, indicating a focus on understanding rather than seeking a definitive solution.

Griffy11
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Hi guys,

Calculate the change in kinetic energy of a car of mass 2000kg if it changes its velocity from 30km/h to 60km/h

KE=1/2mv^2

So, to find the change in KE, subtract its KE when it was going 30km/h from when it was going 60km/h.

At 30km/h:
KE=1/2mv^2
KE=1/2*200*8.33^2
KE=69389J

At 60km/h:
KE=1/2mv^2
KE=1/2*2000*16.7^2
KE=278890J

So change in KE is 209501-69389
= 209501J

Is that correct, or am I doing it totally wrong?

Also - "explain the source of the energy gain" - would that just be an increase in velocity?
 
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Yes that is correct. The source would be what is producing motion in the car in the first place. So this would be the?
 
The driving force/friction between the tires and the road?
 
Well I'd just say it is the engine.
 
Alright great, thanks for your help! :)
 

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