I already found this equation:(adsbygoogle = window.adsbygoogle || []).push({});

T= 15/1.36(.6*sin(t)-cos(t))+100-23.971/e^(.6t)

Now I'm supposed to find the range of temperatures (T) as t approaches infinity.

I tried 100+(15/1.36*.6*sin(90))

and 100-(15/1.36*cos(0))

but that's not right. What am I missing?

Thanks.

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# Quick limit question

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