- #1
- 459
- 0
I have found that ##J = m r^2 \sin^2 \theta \dot{\phi}^2 ## is a constant of motion. How is this orbital angular momentum in the ##\theta = 0 ## direction? It is a particle moving in a central force field.
If you draw a "horizontal" circle, it has radius rsinθ, and the component of velocity parallel to the circle is φ'rsinθI have found that ##J = m r^2 \sin^2 \theta \dot{\phi}^2 ## is a constant of motion. How is this orbital angular momentum in the ##\theta = 0 ## direction?