Quick question about magnetic field inside a wire

AI Thread Summary
The discussion centers on the uniformity of the magnetic field inside a hole in a wire carrying current. It is questioned whether the magnetic field strength varies between the edges of the hole, with concerns about the influence of current density. The calculations for the magnetic field at different points yield different results, leading to confusion about why they are not equal. The key point is that the total current outside the hole balances the magnetic field strength, resulting in a uniform field inside the hole. Ultimately, the uniformity arises from the symmetrical distribution of current around the hole.
Fusilli_Jerry89
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There is a wire of radius r with a current i flowing through it. There is also a hole of radius a in the wire a distance b from the centre of the wire. The question asks, can you show that the magnetic field inside the hole is uniform? (assume that if you impose a current in the opposite direction where the hole is, that current has the same current density as in the actual conductor.)

My question is: how is the field inside the hole uniform? If the magnetic field gets stronger as r increases (the distance from the centre of the wire to anywhere in the wire), then wouldn't the magnetic field be larger at the outside edge of the hole rather than the inside edge? At both edges of the hole, the imposed opposite current would cause the same magnitude of B, would it not?
 
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actually I think I got it? There's more total current when you are on the outside of the hole, so it balances out with the increased magnetic field of the wire without the hole?

But I solved B at the middle and outside edge of the hole to be : B = (mu)ib/2(pi)(R^2 - a^2), but when I solve for B on the inside endge of the hole I get
B2(pi)(b-a) = (mu)j(pi)(b-a)^2 where j = i/pi(R^2 - a^2) and eventually get B = (mu)i(b-a)/2pi(R^2 - a^2).

Why aren't they the same?
 
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