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Quick question about surjective functions

  1. Aug 11, 2009 #1
    Question Details:
    f(a/b) = 2^a * 3^b where (a/b) is in lowest terms.

    Show f is surjective (onto).

    Note: f maps positive integers to natural numbers


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    Is it sufficient to say that...

    It is onto because for every natural number y there is (a/b) s.t. f(x) = y.
     
  2. jcsd
  3. Aug 11, 2009 #2
    I think you have misunderstood the question.
    f(a/b) suggests that f maps from rational numbers and not positive integers. If it mapped from positive integers we would have b=1 always. However even then f isn't surjective. Can you find an a/b in lowest terms such that 2^a * 3^b = 5?

    No. Here you just state the definition of a surjective function. You never show that y actually exists.

    Perhaps you're really supposed to show it's injective as a function from the rational numbers to the natural numbers?
     
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