Quick question on Pulley Force Problems

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Homework Help Overview

The problem involves a block connected to a bucket via a pulley system, focusing on the effects of added mass on acceleration while considering frictional forces. The context includes static and kinetic friction coefficients and the need to calculate net forces and acceleration.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of net force and the appropriate masses to consider in the equation for acceleration. There is an emphasis on analyzing the system through free body diagrams (FBDs) and the impact of friction.

Discussion Status

Some participants have offered guidance on recalculating net forces and suggested using separate equations for different parts of the system. The original poster has identified an oversight regarding the mass of the bucket, indicating progress in understanding the problem.

Contextual Notes

Participants are navigating the complexities of combining static and kinetic friction in their calculations, and there is a focus on ensuring all relevant masses are included in the analysis.

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Alright, so I'm doing this homework problem: "A 32·kg block is connected to an empty 1·kg bucket by a cord running over a frictionless pulley. The coefficient of static friction between the table and the block is 0.41 and the coefficient of kinetic friction between the table and the block is 0.34." And I need to find out the acceleration if 6.1kg of sand is put in the bucket, which I figured out is 0. Now I'm trying to find the acceleration if 7.3kg MORE is put in the bucket.

I have my Fnet as +24.696. When I put it in the equation Fnet=ma, to solve for the a, what masses do I use. Do I have it set up as 24.696=(32+13.4+1)a? Because I have that right now and it's giving me .53 which isn't the right answer. Where did I go wrong in that calculation?
 
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Looks like your net force calculation is wrong, maybe you have made a math error. Please show how you arrived at it.
It is often not wise to look at the combined system of masses in one fell swoop . You instead should look at FBDs of each part of the system separately, getting 2 equations with 2 unknowns you can solve.
 
Once the additional 7.3 kg are added and you find that the gravitational force is enough to overcome the static frictional force, you have to use the coefficient of kinetic friction to calculate that force. That should correct the problem.
 
I actually just figured out what I did wrong. I forgot to incorporate the 1kg of the empty bucket into it. Thank you!
 

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