Quicklime production

  • Thread starter chawki
  • Start date
  • #1
510
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Homework Statement


Quicklime (CaO) is produced by the thermal decomposition of calcium carbonate
(CaCO3).

Homework Equations


Calculate the volume of CO2 produced at STP from the decomposition
of 152 g of CaCO3 according to the reaction
CaCO3 (s) -----> CaO(s) + CO2(g)


The Attempt at a Solution


isn't 22.4L ?
all i could find is the mass of co2
CaCO3 (s) -----> CaO(s) + CO2(g)
100.08g/mol 44g/mol
152g x
x = 66.82g of CO2
mco2 = 66.82
but then how to find the volume???? :grumpy:
 

Answers and Replies

  • #2
chemisttree
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Use PV=nRT

You know everything but V. Watch your units so everything comes out in L.
 
  • #3
510
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P=1atm
T=273,15K
n=1.51mol
R=0.082
V=33.82L
True?
 
  • #4
510
0
Hello people
 
  • #5
chemisttree
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Your multiplication is wrong. Try again.
 
  • #6
510
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PV = nRT
V=(nRT)/P
V=(1.51*0.082*273.15)/1
V=33.82L
 
  • #7
chemisttree
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That part was right. What did you get for n?
 
  • #8
510
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what do you mean ? n = 1.51mol
 
  • #9
chemisttree
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66.82g of CO2/44g CO2/mol CO2 = 1.518636364 mol CO2 = 1.52 mol CO2

V=(1.52*0.082*273.15)/1 = ?

Do you need to use significant figures in your answer? If so, R is not 0.082 as well.
 
  • #10
510
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No, they didn't ask to round on the answer.
 

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