Radial distribution probability

AI Thread Summary
To find the probability of locating an electron within a sphere of a certain radius, one should integrate the radial distribution probability function from 0 to R, where R is the radius of the sphere. The differential probability of finding the particle in a shell of thickness dr at radius r is given by dP=|\psi|^2 4πr²dr. The total probability within the sphere can be calculated using the integral P=∫₀ᴿ |\psi|² 4πr²dr. The factor 4πr² accounts for the surface area of a sphere, emphasizing the radial nature of the distribution. For more complex wavefunctions, additional integrations may be necessary.
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Homework Statement


When I'm trying to find the probability of finding an electron within a sphere of a certain radius, do i integrate the radial distribution probability function with respect to r from 0 to infinity? My book says the product of the radial distribution function times dr would give the probability, but I always thought you had to integrate it.


Homework Equations


n/a just looking for a simple answer to my question... i didnt show the homework problem cos i want to do it myself i just want this question answered.

The Attempt at a Solution


I've attempted the problem, i just integrated and I want to know if you should integrate.
 
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The probability of finding the particle in a shell of thickness dr having radius r is

dP=|\psi|^2\:4\pi r^2dr

The probability of finding the particle anywhere within a sphere of radius R is

P=\int^R_0 |\psi|^2\:4\pi r^2dr

Does this help?
 
yes! helps a ton! Thank you.
 
Notice that 4\pi r^{2} is the area of the surface of a sphere. This factor looks like that because you only have radial distribution, independent of azimuthal direction,
while if your wavefunction looks like \psi(r,\theta,\phi) things will get a little more complicated, and will involve additional integrations.
 
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