Radial postion - momentum uncertain for 2s Hydrogen

TheRascalKing
Messages
7
Reaction score
0

Homework Statement


I'm trying to calculate delta r * delta p for the Hydrogen atom in the 2s state

Homework Equations


ψ(r) = (1/ 2√π) (1 / 2a)^(3/2) (2 - (r/a)) e^(-r/2a)
where a is the bohr radius

The Attempt at a Solution


I figured out that <r> = 6a, but I'm at a loss as to how to figure out <r2> or <p>.

Using E = (-ke2 / 2a)(1/n2), and p2 = 2mE, i found <p2> = (m/2)(-ke2 / 2a), but I am not 100% sure this is right

EDIT: would <p> = 0 since Hydrogen 2s is spherically symmetric?
 
Last edited:
Physics news on Phys.org
TheRascalKing said:
I figured out that <r> = 6a, but I'm at a loss as to how to figure out <r2> or <p>.
How did you calculate ##\langle r \rangle##?


TheRascalKing said:
Using E = (-ke2 / 2a)(1/n2), and p2 = 2mE, i found <p2> = (m/2)(-ke2 / 2a), but I am not 100% sure this is right
What is ##k##?

TheRascalKing said:
EDIT: would <p> = 0 since Hydrogen 2s is spherically symmetric?
No.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top