Radiation pressure on sphere orbiting earth

the_godfather
Messages
18
Reaction score
0

Homework Statement



A spherical shell of diameter D, filled with hydrogen orbits the earth. The average intensity of solar radiation, in a plane perpendicular to the rays is 1.4kW/m^2. Calculate the total force of solar radiation pushing it off its orbit as a function of the shell's albedo.

Homework Equations



F = P.A
A = (4\pi r^2)/2 = (\pi d)/2
P_r = \left\langle S\right\rangle/c = I/c

The Attempt at a Solution



So far I have used all the substitutions which is simple. What I'm not sure is how to incorporate the albedo. So far I have assumed that all incident radiation is absorbed. Can I add the coefficient as (1 + a) where a = albedo to the front of momentum.
Also, my calculations show that reflected incident rays are sent back the way they come from when/if they are reflected. A plane wave incident on a spherical object though would not reflect back in the direction it came from unless it was on the horizontal axis. My only idea would be to use a solid angle? is this along the right lines?
 
Physics news on Phys.org
the_godfather said:
Can I add the coefficient as (1 + a) where a = albedo to the front of momentum.
Not quite, for the reason below.
Also, my calculations show that reflected incident rays are sent back the way they come from when/if they are reflected. A plane wave incident on a spherical object though would not reflect back in the direction it came from unless it was on the horizontal axis. My only idea would be to use a solid angle?
Not sure what you meant by that. Consider a circular element of the surface with an axis parallel to the incoming radiation. The circle subtends an angle 2 θ at the centre of the sphere and has a width r δθ. What is the the force from the reflection from the circle? What is its component away from the sun?
 
haruspex said:
Not quite, for the reason below.

Not sure what you meant by that. Consider a circular element of the surface with an axis parallel to the incoming radiation. The circle subtends an angle 2 θ at the centre of the sphere and has a width r δθ. What is the the force from the reflection from the circle? What is its component away from the sun?

That didn't help me unfortunately, would you be able to elaborate a bit more please...

My current understanding is that the energy impacting the sphere would depend on the latitude of the sphere, in a way similar to how solar radiation is more intense on the equator than nearer the poles (in general).

d\Omega = \sin \theta ~d\theta ~d\phi
 
the_godfather said:
My current understanding is that the energy impacting the sphere would depend on the latitude of the sphere, in a way similar to how solar radiation is more intense on the equator than nearer the poles (in general).

d\Omega = \sin \theta ~d\theta ~d\phi
That's what I meant, but in this context the 'pole' should be taken as pointing towards the sun. So let's say the sun is above the 'north pole'. Consider a band width rδθ at latitude θ. How much light falls on it and at what angle? In which direction is it reflected? What therefore is the change in momentum of that light? What is the component of that change parallel to the NS axis?
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top