Radiative Heat Transfer Problem

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To calculate the rate of radiative heat transfer in the room, apply Stefan's Law of Radiation using the formula E = εσA(T_hot^4 - T_cold^4). Given the heat source area of 2 m², a temperature of 200°C (473 K), and a mean radiant temperature of 20°C (293 K), along with ε = 0.95 and σ = 5.67 x 10^-11 kW m^-2 K^-4, the calculation yields the radiative heat transfer rate. The difference in temperatures raised to the fourth power is crucial for determining the energy transfer. This approach provides a clear method for solving radiative heat transfer problems in thermal environments. The discussion emphasizes the importance of correctly applying the constants and temperature conversions in the calculations.
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A room has a surface mean radiant temperature of 20oC. if a heat source of area 2 m2 at 200oC is introduced into the centre of the room, what is the rate of radiative heat transfer in kW?

Can anyone help me with this question? I can't find any examples in my notes or online and need help quick ... Thanks guys
 
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TRY TO APPLY STEFAN'S LAW OF RADIATION.
E=sigma*A*T^4
where sigma is stefan's constant.
A is area.
T is temperature.
 
Thanks for the quick reply just noticed there was a bit of information missing from the question ... epsilon =0.95, sigma = 5.67 x 10^-11 kW m^-2 K ^-4

So it must be stefan's constant
 
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