Radius and Interval of Convergence for (3x-2)^2/n 3^n Series

aydin

Homework Statement



find the radius of convergence and interval of convergence of the series


Σ (3x-2)^2 / n 3^n
n=1


Homework Equations





The Attempt at a Solution

 
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You need to clean up your notation a little bit, but the ROC for this series is easily found using any number of tests. Try the ratio test or the limsup test.
 
\sum_{n=1}^\infty \frac{(3x-2)^n}{n n!}
is, I think, what you want.

Ratio test is probably best.
a_n= \frac{|3x-2|^n}{n n!}
and
a_{n+1}= \frac{|3x-2|^{n+1}}{(n+1) (n+1)!}

so the ratio is
\frac{|3x-2|^{n+1}}{(n+1)(n+1)!}\frac{n n!}{|3x-2|^n}= |3x-2|\frac{n}{(n+1)^2}
What is the limit of that as n goes to infinity? If that is less than 1, the series will converge.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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