Calculating Raindrops per Tile: A Density Problem | Solution in Drops/Tile

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Raindrops fall on a tile surface at a density of 4358 drops per square foot, with 13 tiles per square foot. To find the number of drops per tile, the calculation involves dividing the total drops by the number of tiles, resulting in approximately 335.23 drops per tile. The method of division is confirmed as correct to eliminate the square foot units. The solution was validated by participants in the discussion. This approach effectively determines the density of raindrops on individual tiles.
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1. Rain drops fall on a tile surface at a density
of 4358 drops/ft^2. There are 13 tiles/ft^2.
How many drops fall on each tile?
Answer in units of drops/tile



Homework Equations





The Attempt at a Solution


what i did was to divide the amount of raindrops by the amount of tiles, (4358drops/ft^2)/(13tiles/ft^2)= 335.23 raindrops/tile. I'm not so sure if my result is the right one.
 
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also, I think I have to divide, because is the only way of getting rid of my ft^2.
 
Looks right to me.
 
yes! it was right, thanks!
 

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