Random versus ordered combustion temperature

AI Thread Summary
In a rocket engine's combustion chamber, molecules exhibit high random motion. As these molecules exit through the nozzle, they transition to a more ordered state, resulting in an increase in temperature. This temperature rise occurs because the pressure decreases as the molecules leave the chamber. The relationship between pressure and temperature indicates that a decrease in pressure correlates with an increase in temperature. Thus, the temperature of the molecules is greater when they exit the nozzle compared to their temperature in the combustion chamber.
dymand68
Messages
20
Reaction score
0
1. Homework Statement :
Molecules in the combustion chamber of a rocket engine are in a high state of random motion. When the molecules leave through a nozzle in a more ordered state, will their temperature be more, less, or the same as their temperature in the chamber before being exhausted?

Homework Equations

temperature (energy) rises(or falls) as pressure increases (or decreases)

The Attempt at a Solution


temperature is more leaving through the nozzle, in a more ordered state (?)
 
Physics news on Phys.org
The temperature of the molecules will be greater when they leave through the nozzle. This is because as the pressure in the combustion chamber decreases, the temperature of the molecules increases. This increase in pressure is due to the more ordered state of the molecules as they leave through the nozzle.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top