Range of the parameter of sphere intersecting with a plane

Jadehaan
Messages
23
Reaction score
0

Homework Statement


Find the range of the parameter d for which the intersection of the sphere x2+y2+z2=1 and the plane x+y+z=d is non-empty.


Homework Equations


Cartesian coordinates of a sphere:
x=rcos\thetasin\phi
y=rsin\thetasin\phi
z=rcos\phi


r=1

The Attempt at a Solution


I substitute x,y,z in both equations
d=sin\thetasin\phi+cos\phi+cos\thetasin\phi
cos2\thetasin2\phi+sin2\thetasin2\phi+cos2\phi=1

Since sin2\theta+cos2\theta=1
I get 1+cos2\phi=1
This implies that \phi=90
Which solves the first equation for d=sin\theta+cos\theta
Is this right?
Thanks for any help.
 
Physics news on Phys.org
I would think your answer would need to be in the form a ≤ d ≤ b. A simpler approach might be to observe the plane will intersect the sphere if the distance of the plane from the origin is ≤ 1. This can be easily done with vectors and no need for spherical coordinates.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top