Rank the volume of the three points with the weakest first

AI Thread Summary
The discussion revolves around calculating the sound intensity at points A, B, and C from two speakers emitting sound at 13.2 kHz. Participants are attempting to use the Pythagorean theorem to determine the path differences from each speaker to the points, but there is confusion regarding the calculations and the correct distances. The importance of calculating the phase difference based on the distances from both speakers to each point is emphasized, as it affects sound intensity. Clarifications are made about the distances involved, particularly between points H1, H2, and B. Overall, the conversation highlights the challenges faced in applying theoretical concepts to practical calculations in sound wave interference.
Nina stena
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Hey all

1.
Two speakers emit sound in phase with the frequency of 13.2 kHz, the sound from the loudspeakers directed at points A , B and C. Rank the volume of the three points with the weakest first.
speed of sound 340m/s

2.
f8010.jpg


3.
I think I need to use Pythagoras says to calculate the
path difference from H1 TO A. This is what i have done but I am sure it's wrong.

60^2+220^2=52000 root square of (52000)= (20) root square (130). I don't really know what I am doing my self.
 
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You wrote H1 to A, but in fact calculated H1 to B, right? That's fine. You mentioned a path difference, so you need another path length. What two path lengths do you need to compare to find what happens at B?
 
haruspex said:
You wrote H1 to A, but in fact calculated H1 to B, right? That's fine. You mentioned a path difference, so you need another path length. What two path lengths do you need to compare to find what happens at B?
Ohh do you mean i calculated the path to B?Beacuse iam not sure if i calculated the right thing.

Oh you mean i calculated the path to B insted of A? And my idea was to use Pythagorean theorem to calculate the path from H1 to A,B and C and then calculate the path from H2 to A,B,C, then compare everything and see what point in A,B,C are the lowest. But is that even a the right method?

Sorry for my bad english and thank for the answer.
 
Nina stena said:
Ohh do you mean i calculated the path to B?Beacuse iam not sure if i calculated the right thing.

Oh you mean i calculated the path to B insted of A? And my idea was to use Pythagorean theorem to calculate the path from H1 to A,B and C and then calculate the path from H2 to A,B,C, then compare everything and see what point in A,B,C are the lowest. But is that even a the right method?

Sorry for my bad english and thank for the answer.

For each point, you need to know the phase difference for the two speakers sending the sound to the point. To calculate the phase difference, you need the two distances (from each speaker to a point), and you need the wavelength of the sound. Does that help?

Can you write the 6 distances (two for each point)? And what is the wavelength of that frequency in air?
 
berkeman said:
For each point, you need to know the phase difference for the two speakers sending the sound to the point. To calculate the phase difference, you need the two distances (from each speaker to a point), and you need the wavelength of the sound. Does that help?

Can you write the 6 distances (two for each point)? And what is the wavelength of that frequency in air?
It helps a bit, but i don't really know how to write it down and get an answer. I have done pretty good job with the othere quesions on this old exam but this question are impossible.
 
Nina stena said:
It helps a bit, but i don't really know how to write it down and get an answer. I have done pretty good job with the othere quesions on this old exam but this question are impossible.
Let's start with point B. Can you work out the distances from H1 to B and from H2 to B?
 
haruspex said:
Let's start with point B. Can you work out the distances from H1 to B and from H2 to B?

H1-B:
When I sketch , I get a triangle , then I can use the Pythagorean theorem . So i get 60^2+220^2=52000 root square of (52000)= (20) root square (130)But if i calculate the first max with the grating equation, will i get the answer?
 
Nina stena said:
H1-B:
When I sketch , I get a triangle , then I can use the Pythagorean theorem . So i get 60^2+220^2=52000 root square of (52000)= (20) root square (130)But if i calculate the first max with the grating equation, will i get the answer?
Not yet. You need H2-B as well.
 
haruspex said:
Not yet. You need H2-B as well.
H2-B: 60+40=100, 100^2+220^2=58400 root square of 58000= (20) root square of (146)= 214 is that even right?

Here is a better picture:
ds1g4.jpg
 
  • #10
Nina stena said:
H2-B: 60+40=100, 100^2+220^2=58400 root square of 58000= (20) root square of (146)= 214 is that even right?

Here is a better picture:
ds1g4.jpg
How do you get 60+40?
 
  • #11
haruspex said:
How do you get 60+40?

Hmm the length from the middle to B? or is't 60+30? I really don't know iam trying my best.
 
  • #12
Nina stena said:
Hmm the length from the middle to B? or is't 60+30? I really don't know iam trying my best.
We want the distance from H2 to B. Draw a straight line connecting them on your diagram.
 
  • #13
Can i just take then the answer from H1-A (-) the distance 220?

Sorry for all the trouble but iam really trying. I have not been in school for the past 2 month , ( i got diabetes) So i have missed much.
 
  • #14
Nina stena said:
Can i just take then the answer from H1-A (-) the distance 220?

Sorry for all the trouble but iam really trying. I have not been in school for the past 2 month , ( i got diabetes) So i have missed much.
I need to label some more points in your diagram for reference.
Call the point half way between H1 and H2 the point O. This is 30cm from each of H1 and H2, right.
What shape do the four points O, H2, B, A make?
 
  • #15
haruspex said:
I need to label some more points in your diagram for reference.
Call the point half way between H1 and H2 the point O. This is 30cm from each of H1 and H2, right.
What shape do the four points O, H2, B, A make?
rectangle?
 
  • #16
Nina stena said:
rectangle?
Right. How long is the side H2-B?
 
  • #17
haruspex said:
Right. How long is the side H2-B?

Sorry i lost my connection, H2 and H1 have the same distence? Beacuse H1 and H2 have the same hight (220) and the base of the tringel are 30 cm?
 
  • #18
Nina stena said:
Sorry i lost my connection, H2 and H1 have the same distence? Beacuse H1 and H2 have the same hight (220) and the base of the tringel are 30 cm?
You have.the rectangle O-H2-B-A. According to the diagram, what are its dimensions?
 
  • #19
haruspex said:
You have.the rectangle O-H2-B-A. According to the diagram, what are its dimensions?
Oh is H2 to B 220cm??
 
  • #20
Nina stena said:
Oh is H2 to B 220cm??
Yes.
So what is the difference in length between H1-B and H2-B?
 
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