Chemistry Solve Log Rate Law Problem | Step-by-Step Guide for Optimal Results

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The discussion focuses on solving a logarithmic rate law problem, specifically addressing the calculation of log values. It clarifies that the logarithm and antilogarithm effectively cancel each other out in the equation presented. The participants confirm that the natural logarithm of 0.1 equals -2.303, derived from the properties of logarithms. This understanding is essential for accurately applying logarithmic functions in rate law calculations. The conversation emphasizes the importance of grasping these logarithmic principles for optimal results in problem-solving.
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Homework Statement
calculation
Relevant Equations
log problem
my question is in fig.
圖片1.png
 
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log0.1=-2.303
because that is what it is when you calculate it
did you calculate it?

you do not need to calculate it thought as the log and antilog cancel
$$\mathrm{antilog}(-1.040+\log(0.010))=\mathrm{antilog}(-1.040)\cdot\mathrm{antilog}(\log(0.100))
=\mathrm{antilog}(-1.040)\cdot(0.100)$$
 
ln means natural logarithm, base e.
 
TKS i get it
 
$$\ln{0.1}=\ln{\left(\frac{1}{10}\right)}=\ln{1}-\ln{10}=0-2.303=-2.303$$
 
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