Rate of Field Change for Induced Current of Loop

AI Thread Summary
To determine the rate of change of the magnetic field (ΔB/Δt) necessary for an induced current of 0.33 A in a conducting loop with an area of 8.0×10−2 m² and resistance of 110 Ω, the equation ΔB/Δt = I*R/A was used, yielding a result of 450 T/s. There was initial confusion regarding the magnetic flux calculation due to the angle between the area vector and the magnetic field, but it was clarified that cos(0) = 1 applies in this scenario. The discussion highlighted issues with the online physics homework platform, "Mastering Physics," which did not provide clear feedback on the correctness of the answer. Participants expressed frustration over potential errors in the homework's parameters and the significance of figures required. Ultimately, the conversation underscored the complexities of applying Faraday's Law in practical scenarios.
tevatron1
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Homework Statement



A single conducting loop of wire has an area of 8.0×10−2 m^2 and a resistance of 110 Ω. Perpendicular to the plane of the loop is a magnetic field of strength 0.37 T.

At what rate (in T/s) must this field change if the induced current in the loop is to be 0.33 A?

Homework Equations



Trying to solve for ΔB/Δt

The Attempt at a Solution



We have a change in magnetic flux, but it seems to be due to ΔB rather than ΔA, so Δflux = ΔB*Acosθ (However since cos(90) = 0, I'm not sure if this will be correct).

Using Faraday's Law |ε| = N|(Δflux/Δt)|
Substituted Δflux = ΔB*A into Faraday's Law --> ε = N(ΔB*A/Δt)
Substituted the equation for the induced EMF into I = |ε|/R and solved for ΔB/Δt
ΔB/Δt = I*R/A (N=1 because the loop has 1 turn)

453.75 T/s = (.33A)*(110Ω)/(8.0*10^-2 m^2)
asks for 2 significant digits -> 450 T/s = Final Answer

I'm not sure where I'm going wrong...
 
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tevatron1 said:

Homework Statement






We have a change in magnetic flux, but it seems to be due to ΔB rather than ΔA, so Δflux = ΔB*Acosθ (However since cos(90) = 0, I'm not sure if this will be correct).
[/b]

θ would not be 90 as Area vector and B make 0 angle
 
kushan said:
θ would not be 90 as Area vector and B make 0 angle

Okay, then cos(0) = 1, which would prove that my assumption Δflux = ΔB*A*cos(0) = Δflux = ΔB*A

How does the rest of my thought process look?
 
as as i know you are doing correctly ,
where are you stuck ?
 
kushan said:
as as i know you are doing correctly ,
where are you stuck ?

Mastering Physics tells me this is the wrong answer, though it does not give any explanation as to why.
 
what is " mastering physics "
 
kushan said:
what is " mastering physics "

It's the online website for our physics homework. When you enter your answer, you are told whether or not your answer is correct. You are given 5 attempts, during which the points you earn diminish.
 
Even I am in confusion as they have given magnitude of magnetic field
(which means a constant field ) but asking find at what rate it would vary
 
kushan said:
Even I am in confusion as they have given magnitude of magnetic field
(which means a constant field ) but asking find at what rate it would vary

Yes, I noticed this as well. I purposely left that out of my equation as we are attempting to solve for ΔB/Δt. I assume it's the authors of the homework trying to trick us into thinking the value is necessary. Though I cannot see how it could be.
 
  • #10
I am sorry as I fail to help you further with this problem
 
  • #11
You know the resistance of the loop and you know the current so you should be able to find the induced emf
 
  • #12
"I am sorry as I fail to help you further with this problem "

Thanks, Kushan. I appreciate your help. I think there might be an issue with the website. It wouldn't be the first time.

Technician: You might notice that is exactly what I attempted to do... No worries though.
 
  • #13
As it turns out, the website wanted a different number of significant figures. Albeit, an incorrect number with the given information...
 
  • #14
Thank god
 
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