RC Circuit Analysis: Find di/dt & Show Current=0 After 1 Time Constant

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Discussion Overview

The discussion revolves around analyzing an RC circuit to find the expression for di/dt and to demonstrate that the current approaches zero after one time constant. Participants explore the mathematical relationships involved in the circuit's behavior over time.

Discussion Character

  • Homework-related, Mathematical reasoning

Main Points Raised

  • One participant presents a current equation, i = 0.02e^-2t, and calculates di/dt as -0.04e^-2t.
  • Another participant requests a complete problem description and emphasizes the need for showing work.
  • A later post clarifies the circuit configuration, including a 100V source, a 100µF capacitor, and a 5kΩ resistor, and mentions the task of graphing current over time.
  • There is a discussion about how to find the gradient at a specific time, with a suggestion to substitute the time value into the general equation for gradient.
  • One participant concludes that the current will be zero after one time constant based on their calculations, indicating a drop of 0.02 after 0.5 seconds.

Areas of Agreement / Disagreement

Participants generally agree on the calculations related to the current and its behavior over time, but there is some uncertainty regarding the completeness of the problem description and the steps taken to arrive at the conclusions.

Contextual Notes

Some assumptions about the circuit's behavior and the definitions of time constants may not be fully articulated, and there are unresolved steps in the mathematical reasoning presented.

jendrix
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Homework Statement



Use current equation and find di/dt expression, hence show if initial gradient were maintained the current would be 0 after 1 time constant.



Homework Equations



I calculated RC to be 0.5s i=0.02e^-t/0.5



The Attempt at a Solution



I solved di/dt to be

-0.04e^-2t

i'm stuck where to go next though, can anyone help? Thanks :)
 
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We are not mind readers, please post a COMPLETE problem description and show us your work.
 
Sorry I didn't realize it was linked.The initial circuit was an RC circuit with 100v source in series with a 100uf capacitor and 5kohm resistor.I was then tasked with graphing i vs t for the first 3 seconds and drawing it.After 3 seconds i=5*10^-5

The formula for i was given as 0.02e^-2t

Then calculated CR to be 0.5

Then I had to draw a tangent and estimate the gradient which came out at 0.02/-1.1=-0.018

Then came the question that was asked, hope that helps.
 
You differentiated to find the general equation for gradient as a function of time? Well, when you need to know the gradient at some time t1 you simply substitute the value of t1 for t in your general equation for gradient.

Initial gradient is usually the gradient when t = 0 secs.
 
Thanks, so the gradient would be -0.04, so after 0.5s( one time constant) the current will have dropped by 0.02, so the current will be 0 after one time constant.Thanks so much for your help. :)
 

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