RCR (series-parallel) Circuit Analysis

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SUMMARY

The discussion focuses on analyzing a series-parallel RCR circuit with an AC voltage source. The impedance of the circuit is defined as Z(w) = R + R' / (1 + R'jwC), where R is the series resistor, R' is the parallel resistor, and C is the capacitor. The user seeks to isolate the real and imaginary components of the impedance function to express it in the form f(w) + j*g(w). The suggested solution involves multiplying the numerator and denominator by the complex conjugate of the denominator to facilitate separation of the real and imaginary parts.

PREREQUISITES
  • Understanding of AC circuit analysis
  • Familiarity with impedance calculations
  • Knowledge of complex numbers and their manipulation
  • Basic algebra skills for isolating functions
NEXT STEPS
  • Study the concept of impedance in AC circuits
  • Learn about complex conjugates and their application in circuit analysis
  • Explore the behavior of RCR circuits at varying frequencies
  • Investigate the use of phasors in AC circuit analysis
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Electrical engineering students, circuit designers, and anyone involved in AC circuit analysis and impedance calculations.

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Homework Statement


If the input AC voltage amplitude is Vo and the angular frequency w, find the impedance of the circuit below and the amplitude of the current that the generator provides. What is the behavior of the circuit at very low and at very high frequencies?

This is a circuit with AC source connected to a resistor R that is in series with a resistor R' and capacitor C that are in parallel. No values are given.

Homework Equations


Z(w) = f(w) + j*g(w)

|Z(w)| = sqrt(f^2(w) + g^2(w))

Vo = Io(w) * Z(w)

f(w) = ?, g(w) = ?

The Attempt at a Solution


Z(w) = R + (1/R' + jwC)^-1

Z(w) = R + ( (1 + R'jwC) / R' )^-1

Z(w) = R + R' / (1 + R'*jwC)

I'm stuck after this point; I can't think of any algebra that let's me isolate a function that ends up as f(w) + j*g(w). Help?
 
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Multiply the numerator and the denominator of your fraction by the complex conjugate of the denominator. In this way you have a real denominator. Then you can separate the real from the imaginary part of the equation.
 

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